Analysis of your Chemical Reaction Composition

Analysis of your Chemical Reaction

Goal: To observe a chemical reaction and to use qualitative and evidence to identify this kind of reaction between four choices. Hypothesis: Its likely that among the four possibilities that the second one; 2NaHCO3 (s) Na2CO3 (S)+CO2 (g) + WATER (g) would be the correct method. This is because when acidified, carbonate that contain compounds will decompose to form carbon dioxide plus water plus the resulting stable product probably will be Na2CO3. Materials:

* a hundred and fifty mm relax tubes (2)

5. Test conduit clamp

2. Burner

* Retort stand

* Clay-based triangle

* Iron ring

* Crucible

* Sodium hydrogen bicarbonate (limewater)

Procedure

Part A

1 . Every materials were collected

2 . 0. five g of NaHCO3 was added to a test tube.

several. A evaluation tube was obtained that was filled one quarter with limewater. 4. NaHCO3 was lightly heated pertaining to 2 moments over Bunsen burner, whilst a testube containing lime water occured up to that. 5. Observations were documented

Part W

1 . An information table was prepared

2 . Crucible was cleaned and dried.

several. Mass of crucible was determined

4. 1 ) 7g of NaHCO3 was added to the crucible.

your five. Crucible was placed on a clay triangular, on a ring stand 6. The substance was heated gently intended for 1 tiny and then heated vigorously pertaining to 6 moments. 7. Crucible cooled to get 5 minutes

eight. Mass of crucible and residue were determined.

Observations

Component A

* Lime drinking water turned gloomy

* Drinking water droplets on top of the test conduit

Part W

Object/ Substance| Mass (g)

Mass of crucible| 17. 52g

Mass of crucible and NaHCO3| 19. 23g

Mass of crucible and residue following heating| 18. 58g

Mass of residue| 1 . 06g

Analysis as well as Calculations

1 ) eq 2) 2NaHCO3 (s)--> Na2CO3 (s)+ CO2 +H20

ratio a couple of: 1

eq 3) 2NaHCO3 (s) --> Na2O (s) + 2CO2 +H2O

rate 2: you

2 . frequency 2) 2NaHCO3 (s) Na2CO3 (S)+CO2 (g) + H2O (g)

n=?

m = 1 . 7g

MM= 22. 99 + 1 . 01 + 18 (3)

sama dengan 84. 01 g/mol

n= m as well as MM

n= 1 . six g as well as 84. 01 g/mol

sama dengan 0. 020 mol

Frequency 3) 2NaHCO3 (s) Na2O (S) +2 CO (g) + H2O (g)

n=?

m sama dengan 1 . 7g

MM= 22. 99 & 1 . 01 + 18 (3)

= 84. 01 g/mol

n= m / MM

n= 1 . 7g / 84. 01 g/mol

= 0. 020 mol

3. eq 2) 2NaHCO3 (s) Na2CO3 (S)+CO2 (g) + WATER (g)

2 NaHCO3= you Na2CO3

0. 020 mol X

= 0. 010 mol

m=?

n= 0. 010 mol

MM= 23 (2) + doze. 01 & 16 (3)

= 106. 01 g/mol

m= and x logistik

m= zero. 010 mol x 106. 01 g/mol

= 1 ) 059 g

Eq 3) 2NaHCO3 (s) Na2O (S) +2 COMPANY (g) & H2O (g)

2 NaHCO3= 1 Na2CO3

0. 020 mol X

= 0. 010 mol

m=?

n= 0. 010 mol

MM= twenty three (2) + 16

= 62 g/mol

m= and x MM

m= zero. 010 mol x 62 g/mol

sama dengan 0. sixty two g

4. Based on the previously collected info and the calculations, it would appear that the other equation 2) 2NaHCO3 (s) Na2CO3 (S)+CO2 (g) + H2O (g) is the correct chemical formula because it has a actual sound product mass of 1. 059 g which is only a 0. 001g difference of the theoretical deliver of 1. 06g. As opposed to the third equation 3) 2NaHCO3 (s) Na2O (S) +2 COMPANY (g) & H2O (g) which had a solid merchandise mass of 0. 62 g with a 0. 44g difference of the theoretical deliver of 1. 06g. 5. eq. 2) 2NaHCO3 (s) Na2CO3 (S)+CO2 (g) + WATER (g)

%yield =actual/theoretical back button 100%

%yield = 1 . 059/1. 06 x 100%

= 00%

%error= (1. 06 – 1 . 059 /1. 06) x (100) = zero. 094 %

eq. 3) 2NaHCO3 (s) Na2O (S) +2 COMPANY (g) + H2O (g)

%error= actual/theoretical x totally

% error = 0. 062/1. 059 x completely

= fifty eight. 4%

%error = ( 1 . summer – 0. 62 /1. 06) x (100) sama dengan 42%

Program

The reaction seen in invisalign is a substance decomposition. Decomposition reactions are usually used in everyday life. For example Air flow cleaners employ decomposition reactions to remove harmful chemical substances from the surroundings and replenish them with non-hazardous ones. One other application of decomposition formulas can be when attempting to produce LASER; when CaCO3 is heatedВ the resulting item are calcium supplement oxide and carbon dioxide. This exercise is widely used in today's substance industry. В The...



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